0AGA030.V Datasheet/PDFWhen it comes to electrical systems, safety often takes precedence over convenience. Fuses, such as the OAGA030.V, exist in order to protect these systems from overloads and short circuits. The OAGA030.V is just one of many fuses created for particular applications, in this case being particularly suited for electric motors.
The OAGA030.V is a 30-amp time-delay fuse with voltage ratings of 600/250 volts AC and 300/48 volts DC. This tells us that the fuse will protect a system from surges of up to 600V AC or 300V DC. A time-delay fuse can be used to protect motors, as it allows more current to be drawn for short periods of time without blowing the fuse. This is especially useful when the motor initially starts up, in order to allow the motor to reach its normal speed without setting off the fuse.
The working principle of the OAGA030.V is quite simple. It consists of a glass tube that is placed in between two metal caps. Inside the tube is a wire that is made of a special alloy, and this wire is responsible for holding the entire circuit together. When an overload occurs, either due to a short circuit or an increased load, the current flowing through the circuit increases. This increase in current causes the wire to heat to a specific temperature, at which point it melts and interrupts the circuit.
The OAGA030.V is specifically designed for use with electric motors, and cannot be used with other electrical systems. When choosing the appropriate OAGA030.V for a specific application, it is important to take into consideration the operating voltage of the motor, the power rating of the motor, and the duration for which the motor will be running. All of these factors will help to determine which fuse to use in order to avoid any problems for the motor in the future.
In conclusion, the OAGA030.V is a 30-amp time-delay fuse with voltage ratings of 600/250 volts AC and 300/48 volts DC. It is specifically designed for electric motor applications, and must be selected carefully based on the particular motor in question. When an overload occurs, the wire inside the fuse will heat up and eventually melt, interrupting the circuit and protecting the motor from damages.